November 16

11/9 ~ Calculating the titer of a webbed plate

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Rationale: Counted the plaques on the webbed 10^-2 plate to calculate the titer and calculated the amount of lysate needed to web the plate.

 

Procedure:

  • Retrieved plates from incubation
  • Counted plaques on the 10^-2 and calculated the strength of the titer = (1.27*10^6)
  • Calculated the area of the plate with the equation πr^2 (π[42.5]^2) = (5.671*10^3)
  • Calculated the area of the plaques by measuring the diameters of 10 plaques (Avg. diameter = 1.04mm)
    • Avg. radii = .52mm; used equation πr^2 (π[.52]^2) = (8.491*10^-1)
  • Divided area of the plate by the area of the plaques to obtain 6.6788*10^3, which was then divided by the strength of the titer to get the amount of lysate needed to web the plate (5.25μL)
  • Due to time constraints, parafilmed the 10μL plate to flood on the next lab day

 

Observations:

10^-2 plate with countable plaques

10^-1 with a good amount of plaques; too many plaques to count but gives an indication of how high the lysate is

10μL direct lysate which completely webbed the plate

 

Next Steps/Conclusion: During the next lab day, the researcher will be using the calculations found today to create a webbed plate as well as flooding the lysated plate


Posted November 16, 2018 by justin_yu1 in category Justin Yu

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